๐Ÿฆ– Bellaziraptor

Topic 1

Thermal expansion

Heat something and it gets bigger. The interesting part is why, and the exam-worthy part is that holes, gaps, and cavities get bigger too โ€” they expand exactly as if they were filled with the surrounding material.

On this page

  1. Why materials expand
  2. Linear expansion
  3. Area and volume expansion
  4. The hole rule
  5. Bimetallic strips
  6. Water: the exception that matters
  7. Worked examples

Why materials expand

Atoms in a solid sit in a potential energy well, vibrating about an equilibrium separation. If that well were a symmetric parabola, heating would just widen the vibration and the average separation would not change โ€” solids would not expand at all.

Real interatomic potentials are asymmetric: steep on the close-in side (atoms repel hard when pushed together) and shallow on the far side. Add energy and the vibration widens more to the right than to the left, so the average separation creeps outward. That creep, summed over billions of bonds, is thermal expansion.

U r low T higher T hotter average separation grows
Each horizontal line is the range of vibration at one temperature; the dot is the average separation. Because the well is lopsided, that average slides to the right as the material heats. Symmetric well ⇒ no expansion.

Linear expansion

For a rod, wire, rail, or any length L0, the change in length is proportional to both the original length and the temperature change:

ΔL = α L0 ΔT α = coefficient of linear expansion, units K−1 (identical to °C−1, since a change of 1 K equals a change of 1 °C).

Two things to notice. First, ΔL scales with L0 โ€” a 1 km bridge moves a thousand times as far as a 1 m ruler for the same temperature swing, which is why long structures need expansion joints and short ones do not. Second, α values are around 10−5 K−1, so fractional changes are tiny; keep your significant figures.

Materialα (10−6 K−1)Note
Lead29Soft metals expand a lot
Aluminum24
Brass19The “expands more” half of most bimetallic strips
Copper17
Steel / iron12Matches concrete โ€” that is why reinforced concrete works
Concrete12
Glass (ordinary)9Cracks under thermal shock
Pyrex / borosilicate3.3Low α ⇒ survives oven-to-counter
Invar (Ni–Fe alloy)1.2Engineered to barely move
Representative values near room temperature. α itself drifts with temperature; treat it as constant over the ranges AP uses.
Why reinforced concrete does not tear itself apart

Steel and concrete have nearly identical α. If they did not, every summer–winter cycle would shear the rebar out of the concrete. That coincidence is the reason the material exists.

Area and volume expansion

Expansion is isotropic in an ordinary solid: every dimension grows by the same fractional amount. So a square of side L grows to L(1 + αΔT) on each side, and its area becomes L2(1 + αΔT)2. Expanding that square and dropping the (utterly negligible) α2 term:

ΔA = 2α A0 ΔT      ΔV = 3α V0 ΔT = βV0ΔT β ≈ 3α is the coefficient of volume expansion. Liquids are quoted with β directly, since they have no fixed shape.

The factors of 2 and 3 are just “how many dimensions are growing.” They are not extra physics, and they are worth being able to re-derive in one line rather than memorizing.

Liquidβ (10−6 K−1)
Mercury182
Water (at 20 °C)207
Glycerin485
Gasoline950
Ethanol1120
Liquids expand roughly 10× more than solids โ€” which is exactly what makes a liquid-in-glass thermometer readable.

The hole rule

This is the single most-tested idea on the page.

Rule

A hole expands as if it were made of the surrounding material. Heat a metal plate with a hole in it and the hole gets bigger, not smaller.

The reason is that expansion is a uniform scaling. Imagine photocopying the plate at 100.2% โ€” every feature, including the empty ones, scales up. Nothing about the material “fills in” the hole.

solid outline: cold dashed: heated every length × (1 + αΔT), including the hole’s diameter
Uniform scaling. The hole’s diameter obeys the same Δd = αd0ΔT as any other length in the plate.

Practical consequence: a stuck metal jar lid loosens under hot water partly because the lid’s inner diameter grows. And to fit a tight ring onto a shaft, you heat the ring โ€” or cool the shaft.

Bimetallic strips

Bond two metals with different α face to face. Heat the pair and the high-α metal wants to be longer than the low-α one, but they are glued together โ€” so the strip bends, curving toward the metal that expands less. Cool it below the bonding temperature and it curves the other way.

brass (α = 19) steel (α = 12) At the bonding temperature: straight
Neutral.
brass, longer Heated: bends toward the steel
The metal on the outside of the curve is the one that expanded more.

That bend is a temperature-controlled switch, which is what an old thermostat, a toaster timer, and a car turn-signal flasher all are.

Water: the exception that matters

Between 0 °C and 4 °C, water contracts as you heat it. Its density peaks at about 4 °C and falls off in both directions. Above 4 °C it behaves normally.

max density at 4 °C 0 4 10 20 temperature (°C) ρ 1000 998 kg/mยณ
Vertical scale is stretched hard โ€” the whole variation shown is under 0.2%. The shape, not the size, is the point.

Two consequences worth being able to explain in words:

Worked examples

1. Expansion joint on a bridge

A steel bridge span is 1.20 km long. Local temperatures run from −15 °C in winter to +40 °C in summer. How much gap must the expansion joints absorb?

Setup. αsteel = 12×10−6 K−1, L0 = 1200 m, ΔT = 40 − (−15) = 55 K.

ΔL = (12×10−6)(1200)(55) = 0.79 m

Nearly 80 cm. Note that ΔT is a difference, so it is the same number in K or °C โ€” no conversion needed here.

2. Does the hole get bigger?

An aluminum plate at 20 °C has a circular hole of diameter 2.000 cm. The plate is heated to 120 °C. Find the new diameter.

Key move. Treat the hole’s diameter as an ordinary length in aluminum. Do not try to reason about the metal “squeezing inward” โ€” it does not.

Δd = (24×10−6)(2.000 cm)(100 K) = 0.0048 cm New diameter = 2.000 + 0.0048 = 2.005 cm. Bigger.

Follow-up they like to ask: a steel bolt of diameter 2.002 cm will not fit at 20 °C but slides through once the plate is hot.

3. Overflow โ€” when the container expands too

A 500 mL ordinary-glass beaker is filled to the brim with water at 20 °C, then heated to 80 °C. How much water spills?

Key move. The container expands too, so the spill is the difference of the two volume expansions, not the water’s alone.

ΔVwater = (207×10−6)(500)(60) = 6.21 mL
ΔVglass = 3(9×10−6)(500)(60) = 0.81 mL Glass is quoted with α, so use β = 3α = 27×10−6 K−1.

Spill = 6.21 − 0.81 = 5.4 mL. If the question had used Pyrex (α = 3.3), the glass term would be 0.30 mL and the spill 5.9 mL โ€” closer to the water-only answer, because low-expansion glass barely moves.

4. Conceptual: which way does the strip bend?

A strip is brass on top, invar on the bottom, bonded flat at 25 °C. Describe its shape at 5 °C.

Reason it out. Cooling, so both shrink โ€” but brass (α = 19) shrinks much more than invar (α = 1.2). The top layer becomes the shorter one, so the strip curves upward: it bows with the brass on the inside of the curve.

The general rule: the layer on the outside of the curve is always the one that is currently longer. On heating, that is the high-α metal; on cooling, the low-α one.

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